∫ dx/(3+sin^2x)
=∫ (sin^2x+cos^2x)/(4sin^2x+3cos^2x) dx
=∫ (1+tan^2x)/(3+4tan^2x)dx
=∫ 1/(3+4tan^2x)d tanx
=arctan【(2√3tanx)/3】+C
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