证明:
就是利用两角和与差的余弦公式
cos(A+B)=cosAcosB-sinAsinB ----------(1)
cos(A-B)=cosAcosB+sinAsinB ----------(2)
(2)-(1)
cos(A-B)-cos(A+B)=2sinAsinB
∴ sinAsinB=-(1/2)*[cos(A+B)-cos(A-B)]
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