Q酒放=q酒精m酒精=3×107J/kg×2.8×10-3kg=8.4×104J
Q水吸=Q酒放=8.4×104J
t=t0+
| Q水吸 |
| cm |
| 8.4×104J |
| 4.2×103J/(kg?℃)×0.4kg |
答：酒精能放出8.4×104J的热量，水的温度会升高到70摄氏度．
本文地址： http://www.goggeous.com/g/1/1077337
文章来源：天狐定制
版权声明：除非特别标注，否则均为本站原创文章，转载时请以链接形式注明文章出处。
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-01 20:27:01职业培训
2025-01-01 20:27:00职业培训
2025-01-01 20:26:59职业培训
2025-01-01 20:26:59职业培训
2025-01-01 20:26:58职业培训
2025-01-01 20:26:57职业培训
2025-01-01 20:26:52职业培训
2025-01-01 20:26:51职业培训
2025-01-01 20:26:49职业培训
2025-01-01 20:26:48职业培训
2024-12-09 18:50职业培训
2024-12-01 18:38职业培训
2025-01-02 12:50职业培训
2024-12-23 00:21职业培训
2024-12-30 00:18职业培训
2024-12-31 23:02职业培训
2024-12-22 05:55职业培训
2024-12-31 21:10职业培训
2025-01-08 04:40职业培训
2024-12-22 13:28职业培训
扫码二维码
获取最新动态
