在积分区域D内,因0<=(x+y)/4<=1,故X+Y)/4<=[(X+Y)/4 ]^(1/2)<=[X+Y)/4]^(1/3),因此
A1<A2<A3
本文地址: http://www.goggeous.com/j/1/945094
文章来源:天狐定制
版权声明:除非特别标注,否则均为本站原创文章,转载时请以链接形式注明文章出处。
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2025-01-08职业培训
2024-12-28 01:12:53职业培训
2024-12-28 01:12:53职业培训
2024-12-28 01:12:52职业培训
2024-12-28 01:12:52职业培训
2024-12-28 01:12:44职业培训
2024-12-28 01:12:43职业培训
2024-12-28 01:12:42职业培训
2024-12-28 01:12:41职业培训
2024-12-28 01:12:41职业培训
2024-12-28 01:12:40职业培训
2024-12-15 20:01职业培训
2024-12-08 08:35职业培训
2024-11-29 23:51职业培训
2024-12-27 16:21职业培训
2024-11-28 10:24职业培训
2024-12-07 03:44职业培训
2024-12-05 08:40职业培训
2024-12-10 05:11职业培训
2024-11-27 21:01职业培训
2024-12-06 15:48职业培训
扫码二维码
获取最新动态